Aptitude
problem on trains
Important Formulas
m/s to km/hr conversion:
a m/s = 
a x 18 
km/hr. 5 km/hr to m/s conversion:
a km/hr = 
a x 5 
m/s. 18 Time taken by a train of length l metres to pass a stationery object of length b metres is the time taken by the train to cover (l + b) metres.
two trains or two objects bodies are moving in the same direction at u m/s and v m/s, where u > v, then their relative speed is = (u - v) m/s.
two trains or two objects bodies are moving in opposite directions at u m/s and v m/s, then their relative speed is = (u + v) m/s.
two trains of length a metres and b metres are moving in opposite directions at u m/s and v m/s .
The time taken by the trains to cross each other = (a + b) sec. (u + v) two trains of length a metres and b metres are moving in the same direction at u m/s and v m/s, then their relative speed is = (u - v) m/s.
two trains or two objects bodies are moving in opposite directions at u m/s and v m/s, then their relative speed is = (u + v) m/s.
two trains of length a metres and b metres are moving in the same direction at u m/s and v m/s,
The time taken by the faster train to cross the slower train = (a+b)sec. (u - v) two trains (or bodies) start at the same time from points A and B towards each other and after crossing they take a and b sec in reaching B and A respectively,
(A's speed) : (B's speed) = (b : a)
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